6y+3=4y^2

Solution for 6y+3=4y^2 equation:

6y+3=4y^2

We move all terms to the left:

6y+3-(4y^2)=0

determiningTheFunctionDomain
-4y^2+6y+3=0

a = -4; b = 6; c = +3;
Δ = b2-4ac
Δ = 62-4·(-4)·3
Δ = 84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{84}=\sqrt{4*21}=\sqrt{4}*\sqrt{21}=2\sqrt{21}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{21}}{2*-4}=\frac{-6-2\sqrt{21}}{-8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{21}}{2*-4}=\frac{-6+2\sqrt{21}}{-8}
$